Find a Cartesian equation in standard form for the ellipse with vertices at and , and minor axis of length 2.
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Anonymous says:
Since the conic is ellipse, a > 0. The distance between two vertices is 6 which equals 2a, so a = 3. Minor axis length is 2 which means 2*b = 2, so b=1. Major axis parallel to x axis, the origin is (-4,2) so the cartesian equation is
(x+4)^2/9 + (y-2)^2/1 = 1
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and 
, and minor axis of length 2.
Since the conic is ellipse, a > 0. The distance between two vertices is 6 which equals 2a, so a = 3. Minor axis length is 2 which means 2*b = 2, so b=1. Major axis parallel to x axis, the origin is (-4,2) so the cartesian equation is
(x+4)^2/9 + (y-2)^2/1 = 1