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Compute the sum of the series ∑ (-1)n x2n

Find all x \in \mathbb{R} such that the series

    \[ \sum_{n=0}^{\infty} (-1)^n x^{2n} \]

converges and compute the sum.


We have

    \[ \sum_{n=0}^{\infty} (-1)^n x^{2n} = \sum_{n=0}^{\infty} (-x^2)^n = \frac{1}{1-(-x^2)} = \frac{1}{1+x^2} \]

by the expansion for the geometric series. This is convergent for |x| < 1.

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