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Find all z such that the series zn / 3n

Find all complex numbers z such that the series

    \[ \sum_{n=1}^{\infty} \frac{z^n}{3^n} \]

converges.


We can write

    \[  \sum_{n=1}^{\infty} \left|\frac{z^n}{3^n}\right| = \sum_{n=1}^{\infty} \left|\left( \frac{z}{3} \right)^n\right|. \]

This is a geometric series, and so converges absolutely for \left| \frac{z}{3} \right| < 1 which implies |z| < 3, and diverges for |z| \geq 3.

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