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Without justification, establish the given formula

Obtain the following formula without attempting to justify the steps used in the process.

    \[ \sum_{n=1}^{\infty} n^3x^n = \frac{x^3 + 4x^2 + x}{(1-x)^4}. \]


Starting with the formula

    \[ \sum_{n=1}^{\infty} n^2 x^n = \frac{x+x^2}{(1-x)^3} \]

we derived in the previous exercise (Section 10.7, Exercise #12) we have

    \begin{align*}  && \sum_{n=1}^{\infty} n^2 x^n &= \frac{x+x^2}{(1-x)^3} \\[9pt]  \implies && \sum_{n=1}^{\infty} n^x x^{n-1} &= \frac{x^2+4x+1}{(1-x)^4} &(\text{differentiating})\\[9pt]  \implies && \sum_{n=1}^{\infty} n^3 x^n &= \frac{x^3 + 4x^2 + x}{(1-x)^4} &(\text{multiplying by } x). \end{align*}

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