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Use differential equations to find the amount of radium after 100 years

Use an appropriate first-order differential equation to find the percentage of a given quantity of radium which remains after 100 years if we are told that the half-life of radium is 1600 years.


We know (example 1 on page 313 of Apostol) that radioactive decay is modeled by the first-order differential equation

    \[ y' = -ky. \]

All solutions to this equation are of the form f(t) = f(0) e^{-kt}. We are given that

    \[ f(1600) = \frac{1}{2}. \]

Therefore,

    \[ f(t) = e^{-kt} \quad \implies \quad e^{-1600k} = \frac{1}{2}. \]

Hence,

    \[ -k = -\frac{1}{1600} \log 2 \quad \implies \quad k = \log 2^{\frac{1}{1600}}. \]

Therefore,

    \[ f(100) = e^{-\log 2^{\frac{1}{16}}} = 2^{-\frac{1}{16}}. \]

Thus, the percentage remaining after 100 years is

    \[ 100(1-2^{\frac{1}{16}}) = 4.2\% \]

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