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Find all solutions of the differential equation y′′ – 2y′ + 3y = 0

by RoRi

Find all solutions of the second-order linear differential equation

    \[ y'' -2y' + 3y = 0 \]

on the interval (-\infty, +\infty).

The given second-order linear differential equation is of the form

    \[ y'' + ay' + by = 0 \qquad \text{with} \qquad a = -2, \quad b = 3.\]

These values of a and b give us d = a^2 - 4b = -8. Hence, d < 0 and k = \frac{1}{2}\sqrt{-d} = \sqrt{2}. By Theorem 8.7 (page 326-327 of Apostol) we then have

    \[ y = e^{-\frac{ax}{2}} \left( c_1 u_1(x) + c_2 u_2(x) \right) \qquad \text{where} \qquad u_1 (x) = \cos(kx), \quad u_2 (x) = \sin(kx). \]

Therefore,

    \begin{align*} y &= e^{x} \left( c_1 \cos(\sqrt{2} x) + c_2 \sin ( \sqrt{2} x ) \right). \end{align*}

for constants c_1 and c_2.

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