We use the trig identity and then use L’Hopital’s rule to evaluate,
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Eiji says:
My understanding is that the book has not proved to use the L’Hopital’s rule when the indeterminate form is ∞/∞. You need to show that the equation is lim x -> π 1/((log 2)/(log (sin x))+1+log(cos x)/log (sin x))
Anonymous says:
I agree, my solution is to set t = |sin(x)| and note that t->0+ when x->pi and then apply L’Hopital.
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My understanding is that the book has not proved to use the L’Hopital’s rule when the indeterminate form is ∞/∞. You need to show that the equation is lim x -> π 1/((log 2)/(log (sin x))+1+log(cos x)/log (sin x))
I agree, my solution is to set t = |sin(x)| and note that t->0+ when x->pi and then apply L’Hopital.