Find the derivative of the function
First, we take the logarithm of both sides so we can use logarithmic differentiation,
Then we differentiate both sides,
Therefore,
Find the derivative of the function
First, we take the logarithm of both sides so we can use logarithmic differentiation,
Then we differentiate both sides,
Therefore,
This doesn’t address the issue of when
, which it is, on the interval
, in which case
is not defined.
And also when
.
I got (1/3)log(3-x)=-1/(3*(3-x)), but you seem to be saying (1/3)log(3-x)=+1/(3*(3-x)). Therefore, I am confused.