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Prove there is no polynomial with derivative 1/x

Prove that there is no polynomial f such that

    \[ f'(x) = \frac{1}{x}. \]


Proof. We know from Example 1 of Section 4.5 in Apostol (p. 166) that every polynomial is differentiable everywhere on \mathbb{R}. (In that example we show that the derivative of a polynomial is a polynomial, and we know that polynomials are defined everywhere on \mathbb{R}.) However, the function \frac{1}{x} is not defined for x = 0. Hence, this function cannot be the derivative of a polynomial. \qquad \blacksquare

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