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Find the largest cylinder that can be inscribed in a cone

Consider a right circular cylinder with radius R and altitude H. Find the right circular cylinder of largest lateral surface area that can be inscribed in this cone.


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The lateral surface area of the cylinder is given by A = 2 \pi r h, where r is the radius of the cylinder and h is the height of the cylinder. From the diagram we find a formula for h in terms of the constants H and R, and the radius of the cylinder r,

    \[ h = - \frac{H}{R}r + H. \]

Thus, letting f(r) denote the lateral surface area we have

    \begin{align*}  A = f(r) = 2 \pi r h &= 2 \pi r \left( - \frac{H}{R} r + H \right) \\  &= 2 \pi r H - \frac{2 \pi H}{R} r^2. \end{align*}

Taking the derivative of this with respect to r and setting it equal to zero,

    \[ 2 \pi H - \frac{4 \pi H}{R} r = 0 \quad \implies \quad R - 2r = 0 \quad \implies \quad r = \frac{R}{2}. \]

Since

    \begin{align*}  f'(r) &> 0 & \text{when} && r &< \frac{R}{2} \\  f'(r) &< 0 & \text{when} && r &> \frac{R}{2} \end{align*}

Therefore, this critical point is a maximum.
Then plugging this back into our expression for h we have

    \[ h = \frac{1}{2} H. \]

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