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Find the largest cylinder (in terms of volume) that can be inscribed in a given cone

Given a right circular cone with radius R and height H, find the right circular cylinder of maximum volume that can be inscribed in the cone.


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The setup is the same as in the previous exercise, except this time we want to maximize the volume V = \pi r^2 h instead of the lateral surface area. Again, we have the following expression for h,

    \[ h = \left( \frac{-H}{R} r + H \right). \]

Then,

    \[ V = \pi r^2 h = \pi r^2 \left( -\frac{H}{R} r + H \right) = \pi H r^2 - \frac{\pi H}{R}r^3. \]

Taking the derivative of this with respect to r,

    \[ \frac{dV}{dr} = 2 \pi H r - \frac{3 \pi H}{R} r^2. \]

Setting this equal to 0 we have,

    \begin{align*}  \frac{dV}{dr} = 0 && \implies && 2 \pi H r - \frac{3 \pi H}{R} r^2 &= 0 \\  && \implies && 2 \pi H - \frac{ 3 \pi H}{R} r &= 0 &(r \neq 0) \\  && \implies && 1 - \frac{3}{2R} r &= 0 \\  && \implies && r = \frac{2R}{3}. \end{align*}

Plugging this into our expression for h we then have

    \[ h = \frac{H}{3}. \]

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