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Evaluate the limit

Evaluate

    \[ \lim_{t \to 0} (sin (2t) + t^2 \cos (5t)). \]


We know (Example 3, p. 134 of Apostol) that sine and cosine are continuous. Further, we know that t^2 is continuous since it is a polynomial. Thus, by Theorem 3.2, t^2 \cos (5t) is continuous since it is a product of continuous functions. By Theorem 3.2 again, \sin (2t) + t^2 \cos (5t) is continuous since it is the sum of continuous functions. Therefore, we can compute the limit by evaluating at t = 0,

    \[ \lim_{t \to 0} \left( \sin (2t) + t^2 \cos (5t) \right) = \sin 0 + 0 \cdot \cos 0 = 0. \]

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