Assuming a spring obey’s Hooke’s law, and assuming a ten-pound force stretches a spring \frac{1}{12} feet, calculate how much work is done to stretch the spring 1 foot.
First, we have stretching the spring feet requires 10 pounds of force, so by Hooke’s law,
Then, we compute the work done stretching the spring 1 foot,
suppose to be 60*x^2 instead of (x^2)/(60)