Proof. Let . Then is a partition of and is constant on the open subintervals of . Further, for we have . Thus, we have (using this exercise and this exercise to evaluate some of the sums),
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mrseb says:
You are helping me a lot with the “proof writing”, thanks a lot.
Just one little minor thing: in point b there is a typo , is n**2 instead of n.
Thanks again! :)
Anonymous says:
In part b, is mathematical induction valid?
Point out an error, ask a question, offer an alternative solution (to use Latex type [latexpage] at the top of your comment): Cancel reply
You are helping me a lot with the “proof writing”, thanks a lot.
Just one little minor thing: in point b there is a typo , is n**2 instead of n.
Thanks again! :)
In part b, is mathematical induction valid?