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# Find solutions of 2xyy′ + (1+x)y2 = ex for given initial values

Find all solutions of the nonlinear differential equation on the interval satisfying the initial conditions

1. when ;
2. when ;
3. a finite limit as .

From a previous exercise (Section 8.5, Exercise #13) we know that a function which is never zero on an interval is a solution of the initial value problem if and only if on where is the unique solution of the initial-value problem 1. In the present problem we have the equation Therefore, to apply the previous exercise we have Hence, is a solution to the given equation if and only if where is the unique solution to We can solve this using Theorem 8.3 (page 310 of Apostol), first computing giving us Therefore, 2. From part (a) we have which implies . Since we then have 3. Let where is some finite real number. Then, (using the calculations we already completed in part (a) and just changing the initial-values and ) Then, Therefore, 