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Compute the area and volume of solids of revolution of e-2x

Define the function for all . Let Compute

1. A(t);
2. V(t);
3. W(t);
4. .

1. The area of the ordinate set on is given by the integral, 2. The volume of the solid of revolution obtained by rotating about the -axis is 3. To compute the volume of the solid of revolution obtained by rotating about the -axis we first find as a function of . Since , the integral is then from to 1 and we have 4. Finally, using parts (c) and (d) we can compute the limit, 1. Artem says:

The solution (c) is incorrect: you need to use the integral of . This will not directly take one to the ending answer. After the integral is computed (can be easily done with integration by parts), you have to add to the result – this is the portion of the solid of revolution, that lies below the , it is a square, which revolves around the y-axis. This will give the answer in Apostol. If sth, one can plot this function and immediately see this.

2. Shafil says:

In part c you forgot to square the function . It should be integral of pi x^2
(I think)

• Evangelos says:

This part of the problem was actually meant to get us to use the method of cylinder “shells” in integrating the solid (Circumference * Height, Integrated over dx).

The integral should look like this (I hope my formatting works…): When calculating the integral using integration by parts, I got the correct, back-of-book answer.

Credit to the posters at Stack Exchange for reminding me that the “shell” method is a thing.
https://math.stackexchange.com/questions/934772/problem-with-volume-of-solid-of-revolution