Consider the formula

By differentiating, determine formulas for the following:

- .
- .

- We observe that
Thus, using the given formula we have,

- (
**Note:**There’s an alternate solution to this in the comments that is more direct than this one. Definitely worth taking a look at that alternative.)

Taking derivatives of both sides of the equation we derived in part (a),Then, looking at the second term in the sum on the left, we have,

Thus, plugging this back into the expression above,

(** Note: ** This is a lot of algebra. I included as many steps as I thought appropriate, but that still has a lot going on in each step. If there is something that isn’t clear please leave a comment. Also, given all of these equations it seems likely I’ve made at least one typo / mathematical error. If you find one, please point it out.)

Ans. to b)

Let the result of a) be $S_1$ and we need to find $S_2$

Since each term in b) is obtained from a) by multiplying x with the derivative of $xS_1$ .

Hence \[

S_2 = x D_x \(xS_1\) \\

= x^2 D_xS_1 + xS_1 \]

Now by finding the derivative of $S_1$ wrt x we get,

\[ D_x \(S_1\) = \dfrac{ \(n+1\)^{2_{\_}}x^{n-1}}{x-1} – \dfrac{2}{x-1}S_1 \]

Where $n^{2_{_2}} $ denotes the Pochammer symbol from quantum Calculus for falling factorial

Now solving for $S_2$ we get,

\[S_2 = \dfrac{\(n^2+n\)x^{n+1}}{x-1} -\dfrac{x^2+x}{x-1}S_1 \]

I hope this method is useful and short as this uses the result of a) to simplify the derivative and please forgive me for my latex errors as I was practicing latex for these last 2 months of Covid -19 quarantine.

Sorry I can’t edit that comment in which I forgot put the latex page command

Ans. to b)

Let the result of a) be and we need to find

Since each term in b) is obtained from a) by multiplying x with the derivative of .

Hence

Now by finding the derivative of wrt x we get,

Where denotes the Pochammer symbol from quantum Calculus for falling factorial

Now solving for we get,

I hope this method is useful and please forgive me for my latex errors as I was practicing latex for these last 2 months of Covid -19 quarantine

Ans. to b)

Let the result of a) be and we need to find

Since each term in b) is obtained from a) by multiplying x with the derivative of .

Hence

Now by finding the derivative of wrt we get,

Where denotes the Pochammer symbol from quantum Calculus for falling factorial

Now solving for we get,

I hope this method is useful

For the part b,

This last step uses the result of part (a).

This provides a direct solution. Hopefully there’s no typo.

Hi, thanks! I retyped your comment into latex so that it’s easier to read. Let me know if I made a mistake. This is a nice solution, that I think works also. I’ll leave the solution I have up there and put a note to look at the comments for this alternative. (I’m not anxious to actually take that derivative since I’ll definitely make an algebra mistake.)