Prove

* Proof. * From this exercise (1.11 #4, part b) we know

But, since is constant on the open subintervals of the partition

which contains every integer between and , we have on the open subintervals of (since there are no integers in the open subintervals). Hence, . Thus,

The partition does not contain all integers. For example, let a = 1.9 and b =3.8. [a] = 1, b-a = 1.9, and [b-a] = 1. Therefore, your proposed partition is 1.9, 2, 3.8. This is missing the integer 3.