Proof. Let . Then is a partition of and is constant on the open subintervals of . Further, for we have . Thus, we have (using this exercise and this exercise to evaluate some of the sums),
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mrseb says:
You are helping me a lot with the “proof writing”, thanks a lot.
Just one little minor thing: in point b there is a typo , is n**2 instead of n.
Thanks again! :)
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You are helping me a lot with the “proof writing”, thanks a lot.
Just one little minor thing: in point b there is a typo , is n**2 instead of n.
Thanks again! :)